x^2-2x=3/8

Solution for x^2-2x=3/8 equation:

x^2-2x=3/8

We move all terms to the left:

x^2-2x-(3/8)=0

We add all the numbers together, and all the variables

x^2-2x-(+3/8)=0

We get rid of parentheses

x^2-2x-3/8=0

We multiply all the terms by the denominator


x^2*8-2x*8-3=0

Wy multiply elements

8x^2-16x-3=0

a = 8; b = -16; c = -3;
Δ = b2-4ac
Δ = -162-4·8·(-3)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{22}}{2*8}=\frac{16-4\sqrt{22}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{22}}{2*8}=\frac{16+4\sqrt{22}}{16}
$